Chargeable weight: actual, volumetric and which one the line bills
Compare scale weight with dimensional weight at three divisors and see which figure sets what you are charged for.
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Run it
The bill is driven by the volumetric weight. The gap between the scale and the bill is 2.5 kg (62.5% of the chargeable figure).
- Move to a flatter box: cutting height by a third often removes the gap entirely.
- Drop the shoe box — it is usually 300–500 g of pure volume.
- Vacuum-pack clothing; textile volume collapses, the scale barely moves.
Formula and method
raw volumetric kg = L(cm) × W(cm) × H(cm) ÷ divisor; volumetric kg = ceil(raw ÷ 0.5) × 0.5; chargeable kg = max(volumetric kg, ceil(actual kg ÷ 0.5) × 0.5); gap kg = chargeable kg − ceil(actual kg ÷ 0.5) × 0.5; gap % = gap kg ÷ chargeable kg × 100; driver = volumetric kg > actual kg ? volumetric : actual kg > volumetric kg ? actual : equal
Rates last checked 2026-10-02. Where a band is missing we print Not verified rather than interpolating between neighbours.
Apply the formula on KakobuyThree worked cases
Case 1
- length: 40
- width: 30
- height: 20
- actualWeight: 1.2
- divisor: 6000
- dimUnit: cm
- weightUnit: kg
Result: 40 × 30 × 20 cm gives 24,000 cm³ ÷ 6000 = 4.00 kg raw, stepped to 4.0 kg volumetric. Actual 1.5 kg after the half-kilogram step, chargeable 4.0 kg. Driver: volumetric. Gap 2.5 kg, or 62.5% of the chargeable weight.
A 24-litre box holding 1.2 kg of clothing is billed at 4.0 kg, so the box is the problem rather than the contents.
Case 2
- length: 50
- width: 40
- height: 10
- actualWeight: 3.2
- divisor: 6000
- dimUnit: cm
- weightUnit: kg
Result: 50 × 40 × 10 cm gives 20,000 cm³ ÷ 6000 = 3.33 kg, stepped up to 3.5 kg volumetric. Actual 3.5 kg, chargeable 3.5 kg. Driver: volumetric, because 3.5 kg exceeds the 3.2 kg on the scale. Gap 0.0 kg (0.0%).
The flat box is the shape to aim for: the volume and the scale weight land on the same half-kilogram step, so nothing is wasted.
Case 3
- length: 16
- width: 12
- height: 8
- actualWeight: 2
- divisor: 6000
- dimUnit: in
- weightUnit: lb
Result: Sides converted to 40.64 × 30.48 × 20.32 cm; raw volumetric 4.20 kg, stepped to 4.5 kg; actual 2 lb = 0.91 kg, stepped to 1.0 kg; chargeable 4.5 kg. Driver: volumetric. Gap 3.5 kg, or 77.8%.
The same box measured in inches and pounds gives the same answer as the metric route, but the 2 lb label hides how far the volume is from the weight.
How to read this gauge
Measure the box before you measure the contents. Three numbers decide what a line charges: the weight on the scale, the weight the dimensions imply, and whichever of the two is larger. Enter the three sides, the scale weight and the divisor, and this gauge returns all three figures side by side plus the gap between them as a weight and as a percentage.
The defaults describe one pair of trainers in its box: 40 × 30 × 20 cm and 1.2 kg. We keep that basket on screen because it is the most common shape we see in the 85 items on this site — a shoe-sized carton that is nowhere near full. The divisor opens at 6000, the middle of the three values lines publish; 5000 flatters bulky goods and 8000 flatters dense ones, so check which figure your line uses before you read the result as a bill.
Conversions run before any rounding. Inches become centimetres at 2.54 and pounds become kilograms at 0.45359237, so an imperial entry and its metric twin produce identical answers. Rounding then happens on the half-kilogram step the lines use: 1.2 kg displays as 1.5 kg, and a raw volumetric figure of 3.33 kg displays as 3.5 kg. The chargeable figure is the larger of those two stepped numbers, and the gap is measured against the stepped actual weight rather than the raw one, which is why the percentage can look smaller than the ratio you expected.
Work one comparison by hand to see why shape matters more than weight. Load 3.2 kg into a flat 50 × 40 × 10 cm carton and the volume is 20,000 cm³, or 3.33 kg, stepped to 3.5 kg — the same step the scale weight lands on, so the gap reads 0.0 kg and the divisor stops mattering. Move the same 3.2 kg into a 30 × 30 × 30 cm cube and the volume rises to 27,000 cm³, or 4.5 kg, and you have bought a kilogram of nothing. That single kilogram is £4.20 on our recorded line structure (reviewed 2026-10-02).
The three worked cases above cover the three readings this tool produces. The default box is volume-driven at 4.0 kg against 1.5 kg of stepped actual weight, a 2.5 kg gap that is 62.5% of the bill. The flat box is the shape to copy, where volume and weight agree and the gap falls to zero. The imperial case shows the same geometry labelled in pounds: 2 lb reads like a light parcel, but 4.5 kg of volumetric weight is what the line will bill, and the gap is 77.8% of the chargeable figure.
Three packing moves repay the effort in order of size. Repack into the flattest carton the contents allow, because height is the cheapest dimension to remove — dropping the default box from 20 cm to 12 cm takes volumetric weight from 4.0 kg to 2.5 kg. Ask for shoeboxes and retail packaging to be taken out before the parcel is sealed, which removes air rather than goods. Vacuum-bag soft goods so a puffer stops holding its own shape. Do these before the parcel is packed, because once it is sealed the measurement is fixed and the charge follows it.
Four boundaries produce a named error instead of a number. A side of zero or less returns "Length must be greater than 0." or the same sentence with the offending side named. Any side above 200 cm returns "Each side must be 200 cm or less — split the parcel above that." A scale weight of zero or less returns "Actual weight must be greater than 0." And an actual weight above 50 kg returns "Above 50 kg most lines require a split — check with the line first." The tool never guesses a divisor you did not choose, and it never reports a chargeable figure below the actual weight.
Send the chargeable figure straight into the landed-cost gauge rather than retyping it, and send both parcels into the merge gauge when a consolidation is on the table. One limit is worth stating plainly: which divisor a given line applies on the day you submit is not something this page can verify, so treat 6000 as a working default and confirm it against the quote on your own parcel page. Where a line publishes 8000, the same box bills a third lighter — the geometry does not change, only the rule applied to it.
Five questions about this gauge
- Which divisor should I choose — 5000, 6000 or 8000?
- Use whichever divisor the line you are booking applies, because that is the only one that predicts your bill. A 24,000 cm³ box is 4.0 kg at 6000, 4.8 kg at 5000 and 3.0 kg at 8000. Where a line does not publish its divisor we mark it Not verified rather than assume 6000, and you can compare all three by changing the one field.
- Why did my 1.2 kg parcel come out at 4.0 kg?
- Because the box is large relative to its contents: 40 × 30 × 20 cm is 24,000 cm³, and 24,000 ÷ 6000 = 4.00 kg of volumetric weight. The line charges the larger of the two figures, so 4.0 kg applies. The 1.2 kg shows up as 1.5 kg after the half-kilogram step, which is the figure the gap is measured against.
- Does a flat box really beat a cube at the same weight?
- At 3.2 kg on the scale, yes. A 50 × 40 × 10 cm box holds 20,000 cm³ and bills at 3.5 kg; a 30 × 30 × 30 cm box holds 27,000 cm³ and bills at 4.5 kg. One kilogram of chargeable weight separates them, and at our recorded £4.20 per kilogram that is £4.20 on the same contents.
- What are the fastest ways to cut volumetric weight?
- Three moves cover most parcels: repack into the flattest box the contents allow, ask for shoeboxes and retail packaging to be removed before the parcel is sealed, and vacuum-bag soft goods so a jacket stops holding air. On the 40 × 30 × 20 cm default, shrinking the height to 12 cm takes the volumetric figure from 4.0 kg to 2.5 kg.
- What happens if I enter inches and pounds?
- The gauge converts before it calculates: 1 inch = 2.54 cm and 1 pound = 0.45359237 kg. A 16 × 12 × 8 in box becomes 40.64 × 30.48 × 20.32 cm, and 2 lb becomes 0.91 kg. Rounding happens after conversion, so an imperial entry and its metric twin always land on the same half-kilogram step.